首页> 外文OA文献 >5-Chloro-1-[(E)-3-(dimethyl­amino)­acrylo­yl]-3-methyl-1H-benzimidazol-2(3H)-one–6-chloro-1-[(E)-3-(dimethyl­amino)­acrylo­yl]-3-methyl-1H-benzimid­azol-2(3H)-one (4/1)
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5-Chloro-1-[(E)-3-(dimethyl­amino)­acrylo­yl]-3-methyl-1H-benzimidazol-2(3H)-one–6-chloro-1-[(E)-3-(dimethyl­amino)­acrylo­yl]-3-methyl-1H-benzimid­azol-2(3H)-one (4/1)

机译:5-氯-1-[[(E)-3-(二甲基氨基)丙烯酰基] -3-甲基-1H-苯并咪唑-2(3H)-一–6-氯-1-[(E)-3-(二甲基氨基)丙烯酰基] -3-甲基-1H-苯并咪唑-2(3H)-一(4/1)

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摘要

In the reaction of 7-chloro-1,5-benzodiazepine-2,4-dione with N,N-dimethyl­formamide/dimethyl­acetal, the diazepine seven-membered ring undergoes a contraction to form the five-membered ring. The reaction yields two isomers the title compound, C13H14ClN3O2; the major component has the chlorine-atom substituent in the 5-position of the benzimidazolone ring and the minor component has the chlorine atom in the 6-position. The two isomers form a disordered co-crystal, the chloro­methyl­benzimidazolone portion of both components are disordered with respect to each other in a 4:1 ratio [the refined ratio is 0.816 (5):0.184 (5)]; the dimethyl­amino­cryloyl substitutent is ordered. The double bond of the dimethyl­amino­acryloyl substituent has an E configuration.
机译:在7-氯-1,5-苯并二氮杂-2,4-二酮与N,N-二甲基­甲酰胺/二甲基­缩醛的反应中,二氮杂seven七元环收缩形成五元环。反应产生两个异构体标题化合物C 13 H 14 ClN 3 O 2。主要成分在苯并咪唑酮环的5-位具有氯原子取代基,次要成分在6-位具有氯原子。两种异构体形成无序共晶体,两种组分的氯­甲基­苯并咪唑酮部分彼此之间以4:1的比例无序排列[精制比例为0.816(5):0.184(5)];订购了二甲基­氨基­丙烯酰基取代基。二甲基­氨基­丙烯酰基取代基的双键具有E构型。

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